How to deserialize JS date using Jackson?

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How to deserialize JS date using Jackson?Error is an illegal operation performed by the user which results in the abnormal working of the program. By now, you’ve probably seen a few errors, either when compiling or running your code like How to deserialize JS date using Jackson?. It can be frustrating, but they can also give you a lot of information about exactly how you can fix the problems in your code about java and json. In this post covers the types of errors you’ll see when programming in Java, and how to fix them. Don’t pay any attention to the number of errors. Just read the first error message and work on fixing that error.

Problem :

I’m getting a date string from ExtJS in the format:


when i try to deserialize this date, it changes the timezone to Indian Standard Time (adds +5:30 to the time) . This is how i’m deserializing the date:

SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");

Doing this also doesn’t change the timezone. I still get the date in IST:

SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");

How do I deserialize the date in the way in which it is coming without the hassles of Timezone?

Solution :

I found a work around but with this I’ll need to annotate each date’s setter throughout the project. Is there a way in which I can specify the format while creating the ObjectMapper?

Here’s what I did:

public class CustomJsonDateDeserializer extends JsonDeserializer<Date>
    public Date deserialize(JsonParser jsonParser,
            DeserializationContext deserializationContext) throws IOException, JsonProcessingException {

        SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
        String date = jsonParser.getText();
        try {
            return format.parse(date);
        } catch (ParseException e) {
            throw new RuntimeException(e);



And annotated each Date field’s setter method with this:

@JsonDeserialize(using = CustomJsonDateDeserializer.class)

This works for me – i am using jackson 2.0.4

ObjectMapper objectMapper = new ObjectMapper();
final DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");

There is a good blog about this topic:
Use @JsonFormat looks the most simple way.

public class Event {
    public String name;

      (shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy hh:mm:ss")
    public Date eventDate;

In addition to Varun Achar’s answer, this is the Java 8 variant I came up with, that uses java.time.LocalDate and ZonedDateTime instead of the old java.util.Date classes.

public class LocalDateDeserializer extends JsonDeserializer<LocalDate> {

    public LocalDate deserialize(JsonParser jsonparser, DeserializationContext deserializationcontext) throws IOException {

        String string = jsonparser.getText();

        if(string.length() > 20) {
            ZonedDateTime zonedDateTime = ZonedDateTime.parse(string);
            return zonedDateTime.toLocalDate();

        return LocalDate.parse(string);

@JsonFormat only work for standard format supported by the jackson version that you are using.

Ex :- compatible with any of standard forms (“yyyy-MM-dd’T’HH:mm:ss.SSSZ”, “yyyy-MM-dd’T’HH:mm:ss.SSS’Z'”, “EEE, dd MMM yyyy HH:mm:ss zzz”, “yyyy-MM-dd”)) for jackson 2.8.6

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